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In a cricket match, five batsmen P, Q, R, S and T scored an average of 36 runs. S Scored 5 more than T; T scored 8 fewer than P; Q scored as many as S and T combined; and Q and R scored 107 between them. How many runs did T score ?

Correct Answer: 20

Let the runs scored by P, Q, R, S and T be  a, b, c, d and e

From given data,

a + b + c + d + e = 36 x 5 = 180b + c = 107Let a = xe = x-8d = x-3now 3x - 11 + 107 = 1803x = 84x = 28e's score = 28-8 = 20

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