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In a cricket match , five batsmen A, B, C, D and E scored an average of 36 runs. D scored 5 more than E, E scored 8 fewer than A, B scored as many as D and E combined, and B and C jointly scored 107. How many runs did E score?

Correct Answer: 20
A+B+C+D+E = 36*5 = 180D = E+5                E = A-8             B = D+E = E+5+E = 2E+5B+C = 107 or, C = 107-B = 107-2E-5 = 102-2EE+8+2E+5+102-2E+E+5+E = 1803E = 180-120E = 60 (Ans.)

In a cricket match, five batsmen A, B, C, D and E scored an average 36 runs. D scored 5 more than E; E scored 8 fewer than A; B scored as many as D and E combined; and B and C jointly scored 107. How many runs did E score?

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