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4 kg of a metal contains 1/5 copper and rest in Zinc. Another 5 kg of metal contains 1/6 copper and rest in Zinc.The ratio of Copper and Zinc into the mixture of these two metals:

Correct Answer: 49 : 221

Copper in 4 kg = 4/5 kg          and      Zinc in 4 kg = 4 x (4/5) kg

 

Copper in 5 kg = 5/6 kg          and      Zinc in 5 kg = 5 x (5/6) kg

 

Therefore, Copper in mixture = 45+56=4930 kg

 

and  Zinc in the mixture = 165+256=22130kg

 

Therefore the required ratio = 49 : 221

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