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What will be output of the following c program ? #include int main() { int max-val=100; int min-val=10; int avg-val; avg-val =( max-val + min-val ) / 2; printf( "%d", avg-val ); return 0; }

Correct Answer: Compilation error

We cannot use special character – in the variable name.Variable name can have only underscore.

What will happens if the statement free(a) is removed in the following C code?
#include<stdio.h>#include<stdlib.h>main(){ int *a; a=(int*)malloc(sizeof(int)); *a=100; printf("*a%d",*a); free(a); a=(int*)malloc(sizeof(int)); *a=200; printf("a%p",a); *a=200; printf("a%d",*a);}

What is the difference between the following 2 C codes?
#include <stdio.h> //Program 1int main(){ int d, a = 1, b = 2; d = a++ + ++b; printf("%d %d %d", d, a, b);}

#include <stdio.h> //Program 2int main(){ int d, a = 1, b = 2; d = a++ +++b; printf("%d %d %d", d, a, b);}

What is the output of this program ? #include
using namespace std;
int n(char, int);
int (*p) (char, int) = n;
int main()
{
(*p)('d', 9);
p(10, 9);
return 0;
}
int n(char c, int i)
{
cout << c << i;
return 0;
}

Comment on the following 2 C programs.
#include <stdio.h> //Program 1int main(){ int a; int b; int c;}#include <stdio.h> //Program 2int main(){ int a; { int b; } { int c; }}

What will be the final values of i and j in the following C code?
#include <stdio.h>int x = 0;int f(){ if (x == 0) return x + 1; else return x - 1;}int g(){ return x++;}int main(){ int i = (f() + g()) | g(); //bitwise or int j = g() | (f() + g()); //bitwise or}

What will be the final values of i and j in the following C code?
#include <stdio.h>int x = 0;int f(){ if (x == 0) return x + 1; else return x - 1;}int g(){ return x++;}int main(){ int i = (f() + g()) || g(); int j = g() || (f() + g());}

Comment on the output of the following C code.
#include <stdio.h>int main(){ int a = 1; switch (a) case 1: printf("%d", a); case 2: printf("%d", a); case 3: printf("%d", a); default: printf("%d", a);}

The following C code is an example of . . . . . . . .
#include<stdio.h>#include<stdlib.h>#include<string.h>main(){ char *p,*q; p=(char*)malloc(3*sizeof(char)); q=p; strcpy(p,"hello"); printf("p=%s",p); printf("q=%s",q); free(q); q=NULL; gets(p); gets(q); printf("%s",p); printf(“%s”,q);}

What is the output of given program if user enter "xyz" ?
#include<stdio.h>void main(){float age, AgeInSeconds;int value;printf("Enter your age:");value=scanf("%f", &age);if(value==0){printf("\\nYour age is not valid");}AgeInSeconds = 365 * 24 * 60 * 60 * age;printf("\\n You have lived for %f seconds", AgeInSeconds);}

Determine output:
#include <stdio.h>void main(){ char *p = NULL; char *q = 0; if(p) printf(" p "); else printf("nullp"); if(q) printf("q"); else printf(" nullq");}