What will be the final values of i and j in the following C code?<br><pre><code class="c-program">#include &lt;stdio.h&gt;int x = 0;int f(){ if (x == 0) return x + 1; else return x - 1;}int g(){ return x++;}int main(){ int i = (f() + g()) | g(); //bitwise or int j = g() | (f() + g()); //bitwise or}</code></pre>

Correct Answer: i value is 1 and j value is undefined