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A straight tree is broken due to thunder storm. The broken part is bent in such a way that the peak touches the ground at an angle elevation of 53°. The peak of the tree touches the ground at a distance of 15 m. What will be the height of the tree?

Correct Answer: 64.58 m
Given, Angle = 53 – degree, base distance = 15 m Let the vertical height be = x m, diagonal length be = y m. ➩ tan 53 = vertical height / base distance ➩ 4 / 3 = x / 25 ➩ x = 100 / 3 m = 33.33 m Also, ➩ sin 53 = vertical height / perpendicular distance ➩ 4 / 5 = 25 / y ➩ y = 125 / 4 m = 31.25 m Height of the tree = x + y = 33.33 + 31.25 m = 64.58 m

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