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2 pipes can fill a tank in 9 minutes when opened simultaneously. If the efficiency of the first pipe is twice the efficiency of the second pipe, find the time required by the second pipe to fill the tank.

Correct Answer: 27 minutes
let the capacity of the tank be 9 liters. Let the efficiency of the second pipe be x. The efficiency of the first pipe = x * 2 = 2x The total relative efficiency = 3x The time required = 9 minutes 9 / 3x = 9 X = 1 / 3 The time required by the second pipe to fill the tank = 9 / x = 9 / 1 / 3 = 9 * 3 = 27 minutes

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