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The specific angular momentum of a hyperbolic trajectory is 94,000 km2/s and the altitude of satellite from earth’s surface is 30,850 km. What is the tangential velocity of the satellite trajectory?

Correct Answer: 2.525 km/s
Given, Satellite altitude from earth (z) = 30,850 km Specific angular momentum (h) = 94,000 km2/s Tangential velocity (vT) = h/r = 94,000/(30,850 + 6378) = 2.525 km/s

A lunar lander is leaving earth on a hyperbolic trajectory with a perigee altitude of 900 km from earth’s surface. The perigee velocity of the trajectory is 14.3 km/s. What is the hyperbolic excess speed? The radius of earth is 6378 km and its gravitational parameter is 398,600 km3/s2.

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What is the tangential velocity of a spacecraft around earth. Given, the orbit is circular, and the specific angular momentum of spacecraft is 57,112 km2/s. Standard gravitational parameter of earth is 398,600 km3/s2?