What is the specific angular momentum of an elliptical orbit, if the flight path angle of the satellite in orbit at an instant is 15°? The satellite is travelling at a velocity of 10.7 km/s at the same instant and is parked at an altitude of 7048 km measured from earth’s center.

Correct Answer: 72,876.32 km2/s
Given, Velocity of satellite (v) = 10.7 km/s Flight path angle (γ) =15° Satellite distance (r) = 7048 km Tangential velocity (vt) = vcos(γ) = 10.7*cos(15°) = 10.34 km/s Specific angular momentum (h) = rvt = 7048*10.34 = 72,876.32 km2/s