What is the area swept by a satellite in an elliptical orbit around earth at t = T/5, where T is the time period of the orbit? Given, semi-major axis and semi-minor axis of the orbit are 9,000 km and 4,000 km respectively.

Correct Answer: 22.62 x 106 km2
Given, Semi-major axis (a) = 9,000 km Semi-minor axis (b) = 4,000 km Area swept (at t = T/5) (A)=? Due to similarity, A/(T/3) = πab/T   || Area of ellipse = πab A = πab/5 = π*9,000*4,000/5 = 22.62 x 106 km2