Two refrigerators M and N operate in series. The refrigerator M absorbs energy at the rate of 1 kW from a body at temperature 400 K and rejects energy as heat to a body at a temperature T. The refrigerator N absorbs the same quantity of energy which is rejected by the refrigerator N from the body at temperature T, and rejects energy as heat to a body at temperature 800 K. If both the refrigerators have the same C.O.P., what is the value temperature T?

Correct Answer: 565.68 K
GiveT1 = 400 K, T2 = 800 K, C.O.P. of M = C.O.P. of N C.O.P. of refrigerator M = T1 / (T2 − T1) = 400 / (T − 400) C.O.P. of refrigerator N = T1 / (T2 − T1) = T / (800 − T) Equating both the C.O.P. we get, 400 / (T − 400) = T / (800 − T) T2 = 400 x 800 T = √320000 T = 565.68 K.