If the angle of wrap on smaller pulley of diameter 250 mm is 1200 and diameter of larger pulley is twice the diameter of smaller pulley, then the centre distance between the pulleys for an open belt drive is

Correct Answer: 250 mm
sin α = (D -d)/2c Angle of wrap on smaller pulley = п – 2α 2п/3 = п – 2sin-1(D -d)/2c c = 250 mm.