The ratio of belt tensions $$\frac{{{{\text{p}}_1}}}{{{{\text{p}}_2}}}$$ considering centrifugal force in flat belt is given by where,<br>m = mass of belt per meter (kg/m)<br>v = belt velocity (m/s)<br>f = coefficient of friction<br>$$\alpha $$ = angle of wrap (radians)

Correct Answer: $$\frac{{{{\text{p}}_1} - {\text{m}}{{\text{v}}^2}}}{{{{\text{p}}_2} - {\text{m}}{{\text{v}}^2}}} = {{\text{e}}^{{\text{f}}\alpha }}$$