Calculate the spacing of 5mm wires having a loss ratio of 0.075, compressive stress is 10.75n/mm2, 5mm diameter wires stress is 1000n/mm2, 12 wires of 8mm diameter are stressed to 1200n/mm2(Nd = 840n/mm2)?

Correct Answer: 11.6mm
ɳ = 0.075, t = 120mm, internal diameter is 30×103, Nd = 840 S = 2×840/0.075x1000x20/10.75x30x103x120 = 11.6mm.