In the manometer given above, 2 immiscible fluids mercury (ρ = 13600 kg/m3) and water (ρ = 1000 kg/m3) are used as manometric fluids. The water end is exposed to atmosphere (100 kP

Correct Answer: 0 kPa
Height of water column = 0.75 + 9.45 = 10.2 m. We equate the pressures at the bottom most point. Pa + ρw.g.(10.2) = Pg + ρm.g.(0.75). We find, Pg = 100 kPa = Absolute pressure. Hence, gauge pressure will be 0.