A father is three time old as old as his son. After fifteen years the will be twice as old as his sons age at that time. Hence the fathers present age-

Correct Answer: 45
Let the ages of the father and his son be F and S respectively. Now,   F = 3S   or,  S = F/3 After 15 years,   F + 15 = 2(S + 15) or,    F + 15 = 2S + 30 or,    F - 2S = 30 - 15 or,    F - 2(F/3) = 15 or,    (3F - 2F)/3 = 15 or,     F = 15 x 3 =  45