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The present age of a father is 3 years more than three times the age of his son. Three years hence, father's age will be 10 years more than twice the age of the son. The father's age is :

Correct Answer: 33 years
Let the present age of Son = x years
And the father's age = 3x + 3
According to the question,
2 (x + 3) + 10 = 3x + 3 + 3
2x + 6 + 10 = 3x + 6
2x + 16 = 3x + 6
x = 10 years
Father's age
= 3 × 10 + 3 = 33 years

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$$\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}$$            is equal to = ?

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