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Given collector resistance = 2kΩ, load resistance = 5kΩ, collector capacitance = 1μF, emitter capacitance = 20μF, collector current = 2mA, source resistance = 2kΩ. If the effect of blocking capacitor is ignored, find the applicable cut-off frequency.

Correct Answer: 612 Hz
RC = 2kΩ, RL = 5kΩ, CC = 1μF, CB = 10μF, CE = 20μF, RS = 2 kΩ hie = 1kΩ, IC = 2mA fL1 = 1/2πCC(RC+RL) = 22.73 Hz fL2 = gm/2πCE = IC/2πCEVT = 612 Hz Since fL2 > 4fL1, hence fL2 is the correct answer.

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