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Determine the value of emitter current and collector current of a transistor having α=0.98 and collector to base leakage current ICBO=4µA. The base current is 50µA.

Correct Answer: 2.7mA
Given, IB=50µA=0.05mA ICBO=4µA=0.004Ma IC=α/(1- α)IB+1/(1- α)ICBO=2.45+0.2=2.65Ma IE=IC+IB=2.65+0.05=2.7mA.

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