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What time does it take for reactants to reduce to 3/4 of initial concentration if the rate constant is 7.5 x 10-3 s-1?

Correct Answer: 38.4s
Given, K=7.5 x 10-3 s-1 K = (2.303/t) x log(0/) t = (2.303/7.5 x 10-3) x log(/) t = (2.303/7.5 x 10-3) x 0.6 t = 38.4s.

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