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Present age of mother is 4 times the sum of the ages of her two daughters, After 5 years, mothers ages will be twice the sum of the ages of the two daughters, What is the present age of the mother?

Correct Answer: 30 years

If two times of the daughters age in years is included to the mothers age, the total is 70 and if two times of the mothers age is included to the daughters age, the total is 95. So the Mothers age is,

Present age of mother is 4 times the sum of the age of her two daughters.After 5 years ,mother's age will be twice the sum of the ages of the two daughters.What is the present age'of mother?

If 6 years are subtracted from the present age of Ayush and takes 25% of that then we get the present age of his only son. 4 years ago, his daughters age is 7 years more than his son. Sum of daughters present age and his wifes present age is 10 years more than Ayushs present age then find the present age of Ayush if average of present age of entire family is 30.25 yr?

Ishikha got married 9 years ago. Today her age is 4/3 times her age at the time of marriage. At present her daughters age is one-sixth of her age. What was her daughters age three years ago?

Eight year ago, Poorvi's age was equal to the sum of the present ages of her one son and one daughter. Five years hence, the respective ratio between the ages of her daughter and her son that time will be 7 : 6. If Poorvi's husband is 7 years elder to her and his present age is three times the present age of their son, what is the present age of the daughter ? (in year)

Simplify the value of $$\frac{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} \times {\text{0}}{\text{.3}} - {\text{3}} \times 0.9 \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}}}}{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} - 0.9 \times {\text{0}}{\text{.2}} - {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}} - 0.3 \times 0.9}} = ?$$

$$\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}$$            is equal to = ?

Each question contains Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly. Quantity I: 3 years ago the ratio of age of A and B is 3: 4 after 2 years the sum of their ages is 45. Then find the present age of A? Quantity II: 5 years ago, the ratio of age of p and Q id 3: 4 Ps age after 6 years is equal to the present age of Q. the find the present age of P?

Rakhi got engaged 10 years ago. Rakhi's present age is 5/3 of her age at the time of engagement. If the present age of Rakhi's mother is twice that ofpresent age of Rakhi, then what was her mother's age (in years) at the time of her engagement?

Farah got married 8 years ago, Today her age is $$1\frac{2}{7}$$ times her age at the time of her marriage. At present her daughter's age is one-sixth of her age. What was her daughter's age 3 years ago ?