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An unbiased coin is tossed five times. The outcome of each toss is either a head or a tail. The probability of getting at least one head is
A
$$\frac{1}{{32}}$$
B
$$\frac{{13}}{{32}}$$
C
$$\frac{{16}}{{32}}$$
D
$$\frac{{31}}{{32}}$$
Correct Answer:
$$\frac{{31}}{{32}}$$
A coin is tossed twice if the coin shows head it is tossed again but if it shows a tail then a die is tossed. If 8 possible outcomes are equally likely. Find the probability that the die shows a number greater than 4, if it is known that the first throw of the coin results in a tail
A
1\/3
B
2\/3
C
2\/5
D
4\/15
For each element in a set of size 2n, an unbiased coin is tossed. All the 2n coin tossed are independent. An element is chosen if the corresponding coin toss were head. The probability that exactly n elements are chosen is
A
\
B
\
C
\
D
$$\frac{1}{2}$$
A fair (unbiased) coin was tossed four times in succession and resulted in the following outcomes: i. Head, ii. Head, iii. Head, iv. Head. The probability of obtaining a 'Tail' when the coin is tossed again is
A
0
B
$$\frac{1}{2}$$
C
$$\frac{4}{5}$$
D
$$\frac{1}{5}$$
The probability is 1/2 that a coin will turn up heads on any toss. If the coin is to be tossed three times, what is the probability that on at least one of the tosses the coin will turn up tails?
A
1/8
B
1/2
C
7/8
D
None of these
A coin is tossed twice. What is the probability of getting head on first toss and tail on second toss?
A
1/2
B
1/3
C
1/4
D
1
Simplify the value of $$\frac{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} \times {\text{0}}{\text{.3}} - {\text{3}} \times 0.9 \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}}}}{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} - 0.9 \times {\text{0}}{\text{.2}} - {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}} - 0.3 \times 0.9}} = ?$$
A
1.4
B
0.054
C
0.8
D
1.0
When tossed, a certain coin has equal probability of landing on either side. If the coin is tossed 3 times, what is the probability that it will land on the same side each time?
A
1/8
B
1/4
C
1/3
D
3/8
$$\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}$$ is equal to = ?
A
24
B
32
C
44
D
100
A fair coin is thrown in the air four times. If the coin lands with the head up on the first three tosses, what is the probability that the coin will land with the head up on the fourth toss ?
A
3/4
B
1/2
C
1/8
D
1/16
An unbiased coin is tossed an infinite number of times. The probability that the fourth head appears at the tenth toss is
A
0.067
B
0.073
C
0.082
D
0.091