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According to maximum shear stress failure criterion, yielding in material occurs, when the maximum shear stress is equal to __________ times the yield stress.
A
0.5
B
2
C
$$\sqrt 2 $$
D
$$\sqrt {\frac{3}{2}} $$
Correct Answer:
0.5
Tresca or maximum-shear stress criteria assumes that yielding occurs when the maximum shear stress reaches a value of the shear stress in the uniaxial tension test. Assume the principal stress being σ1, σ2, σ3 where σ1 is largest, and σ3 is the smallest principal stresses. Find the value of minimum shear stress to cause yielding, given that yield stress in tension is equal to σo?
A
τ = σo
B
τ = σo/2
C
τ = σo/3
D
τ = σo/4
Identify the correct statements from the following:
P. 0.2% yield strength of a material implies 0.2% of the yield strength.
Q. Von-Misses yield criterion implies that yielding occurs when the distortion energy reaches a critical value.
R. Radius of the cylinderical Von-Misses yield surface increases as the grain, size of a single phase material decreases.
S. Tresca's yield criterion gives a circular cylinderical surface in the space of the three principal stresses.
A
P, Q
B
Q, R
C
P, R
D
Q, S
Simplify the value of $$\frac{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} \times {\text{0}}{\text{.3}} - {\text{3}} \times 0.9 \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}}}}{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} - 0.9 \times {\text{0}}{\text{.2}} - {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}} - 0.3 \times 0.9}} = ?$$
A
1.4
B
0.054
C
0.8
D
1.0
$$\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}$$ is equal to = ?
A
24
B
32
C
44
D
100
Elastic failure of a material occurs, when the tensile stress equals yield strength, yield point or the elastic limit. Also, the elastic failure occurs according to maximum strain theory, when the maximum tensile strain equals (where, $$\sigma $$ = yield strength and E = modulus of elasticity)
A
E
B
$$\sigma $$
C
$$\frac{\sigma }{{\text{E}}}$$
D
$$\frac{{\text{E}}}{\sigma }$$
Stress analysis of structural material for the submarine gives the state of stress as shown in the figure. The yield strength of the material is 450 MPa. Using Von-mises yielding criteria determine whether yielding will occur or not? If not, what is the factor of safety?
A
Yielding will not occur
B
Yielding will occur, and the factor of safety is 2.5
C
Yielding will occur, and the factor of safety is 1.53
D
Yielding will occur, and the factor of safety is 1.28
Stress analysis of structural material for the submarine gives the state of stress as shown in the figure. The yield strength of the material is 450 MPa. Using Tresca’s yielding criteria determine whether yielding will occur or not? If not, what is the factor of safety?
A
Yielding will not occur
B
Yielding will occur, and the factor of safety is 1.125
C
Yielding will occur, and the factor of safety is 1.53
D
Yielding will occur, and the factor of safety is 1.28
A shaft is subjected to a maximum bending stress of 80 N/mm
2
and maximum shearing stress equal to 30 N/mm
2
at a particular section. If the yield point in tension of the material is 280 N/mm
2
and the maximum shear stress theory of failure is used, then the factor of safety obtained will be
A
2.5
B
2.8
C
3.0
D
3.5
A body starts yielding when it is subjected to stress state with principal stresses of 250 MPa, 50 MPa and - 50 MPa. What is the yield strength of the material. in MPa, if Tresca yield criterion is obeyed?
A
100
B
200
C
300
D
400
The value of constant k in Tresca’s yielding criteria in case of pure shear will be equal to ___________ Given that Principle stress being σ1, σ2, σ3 and yield stress in tension and pure shear are equal to σo and τ.
A
k = σo
B
k = σo/2
C
k = σo/3
D
k = σo/4