The center of gravity of a trapezium with parallel sides 'a' and 'b' lies at a distance of 'y' from the base 'b', as shown in the below figure. The value of 'y' is<br><img src="/images/question-image/mechanical-engineering/engineering-mechanics/1528353535-11.jpg" title="Engineering Mechanics mcq question image" alt="Engineering Mechanics mcq question image">

Correct Answer: $$\frac{{\text{h}}}{3}\left( {\frac{{2{\text{a}} + {\text{b}}}}{{{\text{a}} + {\text{b}}}}} \right)$$