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Moment of inertia of a hollow circular section, as shown in the below figure about an axis perpendicular to the section, is ________ than that about X-X axis.<br> <img src="/images/question-image/mechanical-engineering/engineering-mechanics/1528353415-5.jpg" title="Engineering Mechanics mcq question image" alt="Engineering Mechanics mcq question image">
A
Two times
B
Same
C
Half
D
None of these
Correct Answer:
Two times
The moment of inertia of a uniform sphere of radius, r about an axis passing through its centre is given by $$\frac{2}{5}\left( {\frac{{4\pi }}{3}{r^5}\rho } \right).$$ A rigid sphere of uniform mass density $$\rho $$ and radius R has two smaller spheres of radii $$\frac{R}{2}$$ hollowed out of it as shown in the figure given below.
The moment of inertia of the resulting body about Y-axis is
A
$$\frac{{\pi \rho {R^5}}}{4}$$
B
$$\frac{{5\pi \rho {R^5}}}{{12}}$$
C
$$\frac{{7\pi \rho {R^5}}}{{12}}$$
D
$$\frac{{3\pi \rho {R^5}}}{4}$$
Moment of inertia of a hollow circular section, as shown in the below figure about X-axis, is
A
$$\frac{\pi }{{16}}\left( {{{\text{D}}^2} - {{\text{d}}^2}} \right)$$
B
$$\frac{\pi }{{16}}\left( {{{\text{D}}^3} - {{\text{d}}^3}} \right)$$
C
$$\frac{\pi }{{32}}\left( {{{\text{D}}^4} - {{\text{d}}^4}} \right)$$
D
$$\frac{\pi }{{64}}\left( {{{\text{D}}^4} - {{\text{d}}^4}} \right)$$
Moment of inertia of a hollow rectangular section as shown in the below figure about X-X axis, is
A
$$\frac{{{\text{B}}{{\text{D}}^3}}}{{12}} - \frac{{{\text{b}}{{\text{d}}^3}}}{{12}}$$
B
$$\frac{{{\text{D}}{{\text{B}}^3}}}{{12}} - \frac{{{\text{d}}{{\text{b}}^3}}}{{12}}$$
C
$$\frac{{{\text{B}}{{\text{D}}^3}}}{{36}} - \frac{{{\text{b}}{{\text{d}}^3}}}{{36}}$$
D
$$\frac{{{\text{D}}{{\text{B}}^3}}}{{36}} - \frac{{{\text{d}}{{\text{b}}^3}}}{{36}}$$
The moment of inertia of the shaded portion of the area shown in below figure about the X-axis, is
A
229.34 cm<sup>4</sup>
B
329.34 cm<sup>4</sup>
C
429.34 cm<sup>4</sup>
D
529.34 cm<sup>4</sup>
A circular hole of 50 mm diameter is cut out from a circular disc of 100 mm diameter as shown in the below figure. The center of gravity of the section will lie
A
In the shaded area
B
In the hole
C
At ‘O’
D
None of these
A particle of mass m is attached to a thin uniform rod of length a and mass 4m. The distance of the particle from the centre of mass of the rod is $$\frac{a}{2}.$$
The moment of inertia of the combination about an axis passing through a normal to the rod is
A
$$\frac{{64}}{{48}}m{a^2}$$
B
$$\frac{{91}}{{48}}m{a^2}$$
C
$$\frac{{27}}{{48}}m{a^2}$$
D
$$\frac{{51}}{{48}}m{a^2}$$
A mass m is constrained to move on a horizontal frictionless surface. It is set in circular motion with radius r
0
and angular speed ω
0
by an applied force $$\overrightarrow {\bf{F}} $$ communicated through an inextensible thread that passesthrough a hole on the surface as shown in figure given below. Then, this force is suddenly doubled.
The magnitude of the radial velocity of the mass
A
increases till mass falls into hole
B
decreases till mass falls into hole
C
remains constant
D
becomes zero at radius r<sub>1</sub>, where 0 1 0
A square hole is made in a circular lamina, the diagonal of the square is equal to the radius of the circle as shown in below figure the shift in the centre of gravity is
A
$$\frac{{{\text{r}}\left( {\pi - 0.75} \right)}}{{\left( {\pi - 0.5} \right)}}$$
B
$$\frac{{{\text{r}}\left( {\pi - 0.25} \right)}}{{\left( {\pi - 0.75} \right)}}$$
C
$$\frac{{{\text{r}}\left( {\pi - 0.5} \right)}}{{\left( {\pi - 0.75} \right)}}$$
D
$$\frac{{{\text{r}}\left( {\pi - 0.5} \right)}}{{\left( {\pi - 0.25} \right)}}$$
The moment of the force ‘P’ about ‘O’ as shown in the below figure is
A
P × OA
B
P × OB
C
P × OC
D
P × AC
A vertically immersed surface is shown in the below figure. The distance of its centre of pressure from the water surface is
A
$$\frac{{{\text{b}}{{\text{d}}^2}}}{{12}} + \overline {\text{x}} $$
B
$$\frac{{{{\text{d}}^2}}}{{12\overline {\text{x}} }} + \overline {\text{x}} $$
C
$$\frac{{{{\text{b}}^2}}}{{12}} + \overline {\text{x}} $$
D
$$\frac{{{{\text{d}}^2}}}{{12}} + \overline {\text{x}} $$