x2-2x+1 =0 হলে x12+1x6 এর মান কত?

x2 - 2x  + 1 = 0⇒x2 + 1  = 2x⇒x2 + 1x = 2xx⇒x + 1x = 2⇒(x + 1x)2 = (2)2⇒x2 + 2x.1x + 1x2 = 2⇒x2 + 1x2 = 2 - 2⇒x2 + 1x2 = 0.'. x12 + 1x6 = x12x6  + 1x6 = x12 - 6 + 1x6 = x6  + 1x6 = (x2)3  + 1(x2)3 = (x2 + 1x2)(x4 - x21x2 + 1x4) = (x2 + 1x2)(x4 - 1 + 1x4) = 0×(x4 - 1 + 1x4) = 0