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The average age of A, B And C sis 30 years. If the difference between B's age and A's age is same as the difference between C's age and B's age . If D is 40 years older than B then what is the sum of the age B and D?

Correct Answer: 100 years
ATQ, B - A = C - B = > 2B = A + C Now, A + B + C = 30 x3 = 90 = > B + (A + C) = 90 = > B + 2B = 90 = > 3B = 90 :: B = 30 D's age = 30 + 40 = 70 B + D = 70 + 30 = 100 (Ans) 

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