If 6 men and 8 boys can do a piece of work in 10 days and 26 men and 48 boys can do the same in 2 days , the time taken by 15 men and 20 boys to do the same type of work will be

Correct Answer: 4 days
Given that 6 men and 8 boys can do a piece of work in 10 days 26 men and 48 boys can do the same in 2 days As the work done is equal, 10(6M + 8B) = 2(26M + 48B) 60M + 80B = 52M + 96B = > M = 2B = > B = M/2 ……(1) Now Put (1) in 15M + 20B = > 15M + 10M = 25M Now, 6M + 8B in 10 days = > (6M + 4M) 10 = 100M Then D(25M) = 100M = > D = 4 days.