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A fair coin is tossed 10 times. What is the probability that ONLY the first two tosses will yield heads?
A
$${\left( {\frac{1}{2}} \right)^2}$$
B
$${}^{10}{{\text{C}}_2}{\left( {\frac{1}{2}} \right)^2}$$
C
$${\left( {\frac{1}{2}} \right)^{10}}$$
D
$${}^{10}{{\text{C}}_2}{\left( {\frac{1}{2}} \right)^{10}}$$
Correct Answer:
$${\left( {\frac{1}{2}} \right)^{10}}$$
The probability is 1/2 that a coin will turn up heads on any toss. If the coin is to be tossed three times, what is the probability that on at least one of the tosses the coin will turn up tails?
A
1/8
B
1/2
C
7/8
D
None of these
A fair coin is tossed 11 times. What is the probability that only the first two tosses will yield heads?
A
(1\/2)^11
B
(9)(1\/2)
C
(11C2)(1\/2)^9
D
(1\/2)
A coin is tossed twice if the coin shows head it is tossed again but if it shows a tail then a die is tossed. If 8 possible outcomes are equally likely. Find the probability that the die shows a number greater than 4, if it is known that the first throw of the coin results in a tail
A
1\/3
B
2\/3
C
2\/5
D
4\/15
A fair coin is tossed three times in succession. If the first toss produces a head, then the probability of getting exactly two heads in three tosses is
A
$$\frac{1}{8}$$
B
$$\frac{1}{2}$$
C
$$\frac{3}{8}$$
D
$$\frac{3}{4}$$
Simplify the value of $$\frac{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} \times {\text{0}}{\text{.3}} - {\text{3}} \times 0.9 \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}}}}{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} - 0.9 \times {\text{0}}{\text{.2}} - {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}} - 0.3 \times 0.9}} = ?$$
A
1.4
B
0.054
C
0.8
D
1.0
A fair coin is thrown in the air four times. If the coin lands with the head up on the first three tosses, what is the probability that the coin will land with the head up on the fourth toss ?
A
3/4
B
1/2
C
1/8
D
1/16
$$\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}$$ is equal to = ?
A
24
B
32
C
44
D
100
A fair (unbiased) coin was tossed four times in succession and resulted in the following outcomes: i. Head, ii. Head, iii. Head, iv. Head. The probability of obtaining a 'Tail' when the coin is tossed again is
A
0
B
$$\frac{1}{2}$$
C
$$\frac{4}{5}$$
D
$$\frac{1}{5}$$
160 heads and 240 tails resulted from 400 tosses of a coin. Find a 95% confidence interval for the probability of a head. Does this appear to be a fair coin?
A
Cannot be said to be fair
B
Can be or cannot be said to be fair
C
Can be said to be fair
D
Yes with +1
When tossed, a certain coin has equal probability of landing on either side. If the coin is tossed 3 times, what is the probability that it will land on the same side each time?
A
1/8
B
1/4
C
1/3
D
3/8