If y is the solution of the differential equation<br>$$\eqalign{ &amp; {{\text{y}}^3}\frac{{{\text{dy}}}}{{{\text{dx}}}} + {{\text{x}}^3} = 0, \cr &amp; {\text{y}}\left( 0 \right) = 1 \cr} $$<br>the value of y(-1) is

Correct Answer: 0