In a race where 12 cars are running, the chance that car X will win is $$\frac{1}{6},$$ that Y will win is $$\frac{{1}}{{10}}$$ and that Z will win is $$\frac{{1}}{{8}}$$. Assuming that a dead heat is impossible. Find the chance that one of them will win.

Correct Answer: $$\frac{{47}}{{120}}$$
Required probability = P(X) + P(Y) + P(Z) (all the events are mutually exclusive)
$$\eqalign{ & = \frac{1}{6} + \frac{1}{{10}} + \frac{1}{8} \cr & = \frac{{47}}{{120}} \cr} $$