60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3 : 2 and alloy B has tin and copper in the ratio 1 : 4, the amount of tin in the new alloy is -
Correct Answer: 44 kg
Quantity of tin in 60 kg of A
$$\eqalign{ & = \left( {60 \times \frac{2}{5}} \right)\,{\text{kg}} \cr & = 24\,{\text{kg}} \cr} $$
Quantity of tin in 100 kg of B
$$\eqalign{ & = \left( {100 \times \frac{1}{5}} \right)\,{\text{kg}} \cr & = 20\,{\text{kg}} \cr} $$
∴ Quantity of tin in the new alloy
= (24 + 20) kg
= 44 kg
$$\eqalign{ & = \left( {60 \times \frac{2}{5}} \right)\,{\text{kg}} \cr & = 24\,{\text{kg}} \cr} $$
Quantity of tin in 100 kg of B
$$\eqalign{ & = \left( {100 \times \frac{1}{5}} \right)\,{\text{kg}} \cr & = 20\,{\text{kg}} \cr} $$
∴ Quantity of tin in the new alloy
= (24 + 20) kg
= 44 kg