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A thief sees a jeep at a distance of 250 m, coming towards him at 36 km/h. Thief takes 5 seconds to realize that there is nothing but the police is approaching him by the jeep and start running away from police at 54 km/h. But police realise after 10 second, when the thief starts running away, that he is actually a thief and gives chase at 72 km/h. How long after thief saw police did catchup with him and what is the distance police had travel to do so?

Correct Answer: 65 s, 1150 m
Initial speed of the police = 10 m/sIncreased speed of the Police = 20 m/sSpeed of the thief = 15 m/sInitial difference between speed of thief and police = 250 mAfter 5 seconds difference between thief and police = 200 + (5 × 10) = 250 mNow, the time required by police to catch the thief = $$\frac{{250}}{5}$$ = 50 sTotal time = 50 + 15 = 65 sTotal distance = 1000 + (15 × 10) = 1150 m.

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