Get Advice on Live Video Call
Earn $ Cash $ with
consultations on Bissoy App

Mr A started half an hour later than usual for the marketplace. But by increasing his speed to $$\frac{3}{2}$$ times his usual speed he reached 10 minutes earlier than usual. What is his usual time for this journey?

Correct Answer: 2 hours
Let the usual speed be S.So, increased speed = $$\frac{{3{\text{S}}}}{2}$$Let usual time taken be TThus, S × T = D, and also $$\frac{{3{\text{S}}}}{2}$$ × (T - 40) = D. (T - 40, Because he started 30 minutes later and reached 10 minutes earlier, means he saved 40 minutes)$$\frac{{3{\text{S}}}}{2}$$ × (T - 40) = ST$$\frac{{3 \times {\text{ST}}}}{2}$$  - 60S = ST$$\frac{1}{2}$$ × ST = 60ST = 120 minutes = 2 hoursAlternatively,As, ST = D Speed increase to $$\frac{{3}}{{2}}$$ times so time decreases to $$\frac{{2}}{{3}}$$ times . Net decrease = $$\frac{{1}}{{3}}$$ = 40 minutes.Hence actual time taken
= 3 × 40 = 120 mnts.
= 2 hours

John, Jack, Joseph and Jordan participated in a running race. Only the winner finished the race in 10 minutes. Which two pieces of information can tell you who the winner was? (i) John finished the race in 16 minutes . (ii) Joseph finished the race earlier than Jack by 2 minutes. (iii) Jack finished the race later than Jordan by 4 minutes. (iv) Jordan finished the race earlier than John by 6 minutes. (v) John finished the race later than Joseph by minutes.

Simplify the value of $$\frac{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} \times {\text{0}}{\text{.3}} - {\text{3}} \times 0.9 \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}}}}{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} - 0.9 \times {\text{0}}{\text{.2}} - {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}} - 0.3 \times 0.9}} = ?$$

$$\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}$$            is equal to = ?

The average speed of a train is 20% less on the return journey than on onward journey. The train halts for half an hour at the destination station before starting on the return journey. If the total time taken for the to and fro journey is 23 hours, covering a distance of 1000 km, the speed of the train on the return journey is:

Praneet started his journey at 2:45:46 p.m. and reached the destination at 4:55:57 p.m. Anit started the journey 58 mins 40 secs after Praneet and reached his destination 50 mins 29 secs after him. How long did Anit take to complete his journey?

Sunil started his journey at 2:33:34 p.m. and reached the destination at 4:43:45p.m. Anil started the journey 45 min 27 secs after Sunil and reached the destination 37 mins 16 secs after him. How long did Anil take to complete his journey?

A train travels from New York to Chicago, a distance of approximately 840 miles, at an average rate of 60 miles per hour and arrives in Chicago at 6:00 in the evening , Chicago time . At what hour in the morning, New York City time, did the train depart for Chicago time . At what hour in the morning , New York City time, did the train depart for Chicago ? ( Chicago time is one hour earlier than New York City time.)

One day, Mr. Karim started 30 minutes late from home and reached his office 50 minutes late, while driving 25% slower than his usual speed? How much time in minutes does Mr. Karim usually take to reach his office from home?

The average speed of a train in the onward journey is 25% more than that in the return journey. The train halts for one hour on reaching the destination. The total time taken for the complete to and fro journey is 17 hours, covering a distance of 800 km. The speed of the train in the onward journey is :

A pipe, working at full speed, can fill an empty cistern in 1 hour. However, during the first hour it worked at one-twelfth of its capacity, during the second hour at one-ninth of its capacity, during the third hour at one-sixth of its usual capacity and during the fifth hour it was only one -third as efficient as it was supposed to be. A second pipe also displayed similar performance, but if it worked at full speed would have filled the empty cistern in 2 hours. Together with a drain pipe that drained water out of the tank at a constant rate, the empty cistern could be filled in 5 hours, all the three pipes working concurrently. How many hours will it take the drain pipe to empty the filled cistern if no other pipe was functioning during the time?