Two numbers are in ratio P : Q. when 1 is added to both the numerator and the denominator, the ratio gets changed to $$\frac{{\text{R}}}{{\text{S}}}$$. again, when 1 is added to both the numerator and denominator, it becomes $$\frac{1}{2}$$. Find the sum of P and Q.
Correct Answer: 5
If we go through normal method, It will be quite cumbersome,so, We will solve this question through options
Taking Option A:
It has P + Q = 3.
The possible value of $$\frac{{\text{P}}}{{\text{Q}}}$$ is $$\frac{1}{2}$$ or $$\frac{2}{1}$$Using $$\frac{1}{2}$$, we see that on adding 2 in both the numerator and denominator we get $$\frac{3}{4}$$ (not required value)Similarly we check for $$\frac{2}{1}$$, this will also not give the required valueOption B: We have $$\frac{1}{3}$$ possible ratioThen, we get the final value as $$\frac{3}{5}$$ (not = to $$\frac{1}{2}$$) Hence, rejected Option C: Here we have $$\frac{1}{4}$$ or $$\frac{2}{3}$$Checking for $$\frac{1}{4}$$ we get $$\frac{3}{6}$$ = $$\frac{1}{2}$$
Hence, the option c is correct
Taking Option A:
It has P + Q = 3.
The possible value of $$\frac{{\text{P}}}{{\text{Q}}}$$ is $$\frac{1}{2}$$ or $$\frac{2}{1}$$Using $$\frac{1}{2}$$, we see that on adding 2 in both the numerator and denominator we get $$\frac{3}{4}$$ (not required value)Similarly we check for $$\frac{2}{1}$$, this will also not give the required valueOption B: We have $$\frac{1}{3}$$ possible ratioThen, we get the final value as $$\frac{3}{5}$$ (not = to $$\frac{1}{2}$$) Hence, rejected Option C: Here we have $$\frac{1}{4}$$ or $$\frac{2}{3}$$Checking for $$\frac{1}{4}$$ we get $$\frac{3}{6}$$ = $$\frac{1}{2}$$
Hence, the option c is correct