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The length, breadth and height of a room are in ratio 3:2:1. If breadth and height are halved while the length is doubled, then the total area of the four walls of the room will

Correct Answer: decrease by 30%
Let length, breadth and height of the room be 3, 2, 1 unit respectively. Area of walls = 2(l + b) × h = 2(3 + 2) × 1 = 10 sq. unit. Now, length, breadth and height of room will become 6, 1 and $$\frac{1}{2}$$ respectively. Now, area of walls = $$2\left( {6 + 1} \right) \times \frac{1}{2}$$   = 7 sq. unit. % decrease in the area of walls = $$\left( {10 - 7} \right) \times \frac{{100}}{{10}}$$   = 30%

The length, breadth and height of the room are in the ratio 3 : 2 : 1. The breadth and height of the room are halved and length of the room is doubled. The area of the four walls of the room will :

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