A man sells chocolates which are in the boxes. Only either full box or half a box of chocolates can be purchased from him. A customer comes and buys half the number of boxes which the seller had plus half box more. A second customer comes and purchases half the remaining number of boxes plus half a box. After this the seller is left with no chocolate boxes. How many chocolate boxes the seller had initially?

Correct Answer: 3
The best way to go through the optionsLet there are initially 3 boxes then,1st customer gets = $$\frac{3}{2}$$ + $$\frac{1}{2}$$ = 2Remaining boxes = 3 - 2 = 12nd customer = $$\frac{1}{2}$$ + $$\frac{1}{2}$$ = 1So, option B is correct.