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The batting average for 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. The highest score of the player is

Correct Answer: 174 runs
Let the highest score be x
Then, lowest score = (x - 172)
Then,
⇔ (50 × 40) - = 38 × 48
⇔ 2x = 2000 + 172 - 1824
⇔ 2x = 348
⇔ x = 174

The batting average for 40 innings of a cricket player is 50 runs. His higest score in an innings exceeds his lowest score by 172 runs. if thse two innings are excluded, the average score of the remianing 38 innings is 48 runs . Find his highst score in an innings

The batting average for 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. The highest score of the player is -

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