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The tubs capacity in direct rope haulage varying from when pedestal bearing are used.
A
0.2 - 0.3m<sup>3</sup>
B
0.4 - 0.7m<sup>3</sup>
C
0.8 - 1.1m<sup>3</sup>
D
1.2 - 1.5m<sup>3</sup>
Correct Answer:
0.8 - 1.1m<sup>3</sup>
A direct rope haulage pulls 8 tubs loaded with coal through an incline of length 500 m having an inclination of 1 in 6. Consider the following additional data.
Capacity of tub = 1.0 tonne.
Tare weight of tub = 500 kg
Hauling speed = 9 km per hour
Coefficient of friction between wheel and rail = $$\frac{1}{{60}}$$
Coefficient of friction between rope and drum = $$\frac{1}{{10}}$$
Mass of rope per meter = 1.5 kg
The minimum power required to haul the tubs in kW is
A
345.50
B
348.60
C
350.10
D
365.50
E
58.86
A man ordered a length of rope by telephone from his nearest hardware shop. But when a worker in the shop brought the rope, he found that the man on the telephone had miswritten the order by interchange feet and inches. As a result of this, the length of rope received was only 30% of the length he had ordered. The length of the rope which the man ordered was between :
A
6 ft and 7 inches
B
7$$\frac{1}{2}$$ ft and 9 ft
C
9 ft and 2 inches
D
10$$\frac{1}{2}$$ ft and 12 ft
Two persons are holding a rope of negligible mass horizontally. A 20 kg mass is attached to the rope at the mid-point, as a result, the rope deviates from the horizontal direction. The tension required to completely straighten the rope is (g = 10 m/s
2
)
A
200 N
B
20 N
C
10 N
D
infinitely large
A haulage rope winds on a drum of radius 500 mm, the free end being attached to a truck. The truck has a mass of 500 kg and is initially at rest. The drum is equivalent to a mass of 1250 kg with radius of gyration 450 mm. The rim speed of the drum is 0.75 m/s before the rope tightens. By considering the change in linear momentum of the truck and in the angular momentum of the drum, find the speed of the truck when the motion becomes steady.
A
0.502 m/s
B
0.602 m/s
C
0.702 m/s
D
0.802 m/s
An elevator is assembled to raise equipment to a height of 22m. It is estimated that maximum weight of the material to be raised is 4.9kN. It is observed acceleration in such cases is 1.2m/s².10mm diameter wire ropes with fibre core are used. The tensile designation of the wire is 1500.Number of rope wires is assumed to be 2. Number of rope wires is assumed to be 2. Calculate the total load on wire rope neglecting the bending load if weight of 50m wire is 18kg.
A
1054.55N
B
3504.55N
C
2836.84N
D
5678.6N
A rope 2-.6 meters long cut is into two pieces .If the length of one piece of rope is 2.8 meters shorter than the length of the other , what is the length , in meters, of the longer piece of rope?
A
7.5
B
11.7
C
8.9
D
10.3
A monkey of mass 20 kg is holding a vertical rope. The rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25kg. What is the minimum acceleration with which the monkey can climb up along the rope? (g = 10m/s2)
A
5m/s2
B
10m/s2
C
25m/s2
D
2.5m/s2
A lift of weight W is lifted by a rope with an acceleration f. If the area of cross-section of the rope is A, the stress in the rope is
A
$$\frac{{{\text{W}}\left( {1 + \frac{{\text{f}}}{{\text{g}}}} \right)}}{{\text{A}}}$$
B
$$\frac{{\left( {1 - \frac{{\text{g}}}{{\text{f}}}} \right)}}{{\text{A}}}$$
C
$$\frac{{{\text{W}}\left( {2 + \frac{{\text{f}}}{{\text{g}}}} \right)}}{{\text{A}}}$$
D
$$\frac{{{\text{W}}\left( {2 + \frac{{\text{g}}}{{\text{f}}}} \right)}}{{\text{A}}}$$
Tail rope haulage is mainly used as
A
Main rope haulage
B
Haulage for waste disposal
C
As a buffer haulage inside the district
D
To replace endless haulage
A rotor which is balanced statically but not dynamically is supported on two bearings L apart and at high speed of the rotor, reaction on the left bearing is R. The right side of the bearing is shifted to a new position 2L apart from the left bearing. At the same rotor speed, dynamic reaction on the left bearing in the new arrangement will
A
Remain same as before
B
Become equal to 2R
C
Become equal to $$\frac{{\text{R}}}{2}$$
D
Become equal to $$\frac{{\text{R}}}{4}$$