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Ram and Hari can cut 12 kgs nuts in 2 days. After 5 days, Hari left the work. Ram took 8 more days to cut the rest of the nuts. If total of 58 kgs of nuts were cut, the time taken by Hari to cut 10 kg of nuts is

Correct Answer: 4 days

Directions: Four friends Raghu, Rajesh, Ramesh and Ravi complete their Graduation in different number of years. The one who took maximum time took eight years to complete his Graduation while the one who took least time took only three years to complete it.Ravi took more time only than Raghu and completed his Graduation in five years. Ramesh did not take longer time
than Rajesh to complete his Graduation. Question: Who took more years to complete his graduation among all ?

Mujahid can do a work in 8 days, while has colleagues Asad takes 12 days and Mithun takes 16 days to complete the same.Mujahid and Asad started the work and after few days Asad left the work keeping it incomplete. Rest of the work was completed by Mujahid and Mithun in 2 days.How long it took to complete the whole work?

After working for 8 days, Hari Ram finds that only 1/3 rd of the work has been done. He employs Satya who is 60% as efficient as Hari Ram. How many days more would Satya take to complete the work ?

A started a ,work and left after working for 2 days. Then B was called and he finished the work in 9 days. had A left the work after working for 3 days, B would have finished the remaining work in 6 days. In how many days can each of them, working alone, finish the whole work ?

Ram's son's age is $$\frac{1}{3}$$ of Ram's wife's age. Ram's wife's age is $$\frac{4}{5}$$ of Ram's age and Ram's age is $$\frac{3}{5}$$ of Ram's father's age. Find the age of Ram's son, if Ram's father is 50 years old ?

A and B together can do a piece of work in 10 days. If A can do the work in 15 days, find in how many days that B alone can do the same work. Given below are the steps involved in solving the above problem. Arrange them in sequential order. A) One day's work of B is 1/10 - 1/15 B) One day's work of A and B is 1/10 and One day's work of A is 1/15 C) B alone can do the work in 30 days D) One day's work of B is 1/30

If a + b + c + d = 4, then find the value of $$\frac{1}{{\left( {1 - a} \right)\left( {1 - b} \right)\left( {1 - c} \right)}}$$     + $$\frac{1}{{\left( {1 - b} \right)\left( {1 - c} \right)\left( {1 - d} \right)}}$$     + $$\frac{1}{{\left( {1 - c} \right)\left( {1 - d} \right)\left( {1 - a} \right)}}$$     + $$\frac{1}{{\left( {1 - d} \right)\left( {1 - a} \right)\left( {1 - b} \right)}}$$     is?

If a + b + c + d = 4, then the value of $$\frac{1}{{\left( {1 - a} \right)\left( {1 - b} \right)\left( {1 - c} \right)}}$$     + $$\frac{1}{{\left( {1 - b} \right)\left( {1 - c} \right)\left( {1 - d} \right)}}$$     + $$\frac{1}{{\left( {1 - c} \right)\left( {1 - d} \right)\left( {1 - a} \right)}}$$     + $$\frac{1}{{\left( {1 - d} \right)\left( {1 - a} \right)\left( {1 - b} \right)}}$$     is?

A, B and C can complete a work in 10, 12 and 15 days respectively. They started the work together. But A left the work 5 days before its completion. B also left the work 2 days after A left. In how many days was the work completed ?

X and Y together can do a piece of work in 30 days. Y and Z together can do the work in 20 days. X starts the work and works for 15 days then Y takes that work and works for 27 days. Finally Z finishes the remaining work in 9 days. In how many days Y alone can complete the entire work?