The odds favouring the event of a person hitting a target are 3 to 5. The odds against the event of another person hitting the target are 3 to 2. If each of them fire once at the target, find the probability that both of them hit the target.
Correct Answer: 3\/20
Let A be the event of first person hitting the target,
P(A) =33+5=38 (odd in favour)
Let B be the event of Second person hitting a target.
P(B)=23+2=25 (odd against)
Since both events are independent and both will hit the target so,
P(A∩B)= P(A)P(B)=38×25=320