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Mr. Gupta borrowed a sum of money on compound interest. What will be the amount to be repaid if he is repaying the entire amount at the end of 2 years? I. The rate of interest is 5 p.c.p.a. II. Simple interest fetched on the same amount in one year is Rs. 600. III. The amount borrowed is 10 times the simple interest in 2 years.

Correct Answer: .II and Either I or III only

 

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I. gives, Rate = 5% p.a.

 

II. gives, S.I. for 1 year = Rs. 600.

 

III. gives, sum = 10 x (S.I. for 2 years).

 

Now I, and II give the sum.

 

For this sum, C.I. and hence amount can be obtained.

 

Thus, III is redundant.

 

Again, II gives S.I. for 2 years = Rs. (600 x 2) = Rs. 1200.

 

Now, from III, Sum = Rs. (10 x 1200) = Rs . 12000.

 

Thus, Rate =

 

100 x 1200

 

= 5% p.a.

 

2 x 12000

 

Thus, C.I. for 2 years and therefore, amount can be obtained.

 

Thus, I is redundant.

 

Hence, I or III redundant.

Mr. Gupta borrowed a sum of money on compound interest. What will be the amount to
be repaid if he is repaying the entire amount at the end of 2 years?
I. The rate of interest is 5 p.c.p.a.
II. Simple interest fetched on the same amount in one year is Rs. 600.
III. The amount borrowed is 10 times the simple interest in 2 years.

Rahul borrowed a sum of Rs. 1150 from Amit at the simple interest rate of 6 p.c.p.a. for 3 Years. He then added some more money to the borrowed sum and lent it to Sachin for the same time at 9 p.c.p.a simple interest. If Rahul gains Rs. 274.95 by way of interest on borrowed sum as well as his own amount from the whole transaction, then what is the sum lent by him to Sachin ?

Simplify the value of $$\frac{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} \times {\text{0}}{\text{.3}} - {\text{3}} \times 0.9 \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}}}}{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} - 0.9 \times {\text{0}}{\text{.2}} - {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}} - 0.3 \times 0.9}} = ?$$

$$\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}$$            is equal to = ?

Consider the following statements
If a sum of money is lent at simple interest, then the
I - money gets doubled in 5 years if the rate of interest is $$16\frac{2}{3}$$ %
II - money gets doubled in 5 years if the rate of interest is 20%.
III - money becomes four times in 10 years if it gets doubled in 5 years.

What is the compound interest earned at the end of 3 years? I. Simple interest earned on that amount at the same rate and for the same period is Rs. 4500. II.The rate of interest is 10 p.c.p.a. III.Compound interest for 3 years is more than the simple interest for that period by Rs.465.

Rohan borrowed a certain sum of money at simple interest. Rate of interest was 3% per annum for first 3 years, 4% per annum for next 5 years and6% per annum for next 7 years. If he paid Rs 2059 as interest, then what is the sum borrowed (in Rs)?

A class of 20 students borrowed library books for their research projected. Some of the students borrowed 3 books each, and the rest borrowed 2 books each. If a total of 52 books were borrowed, how many of the students borrowed, how many of the students borrowed 3 books each?

A finance company declares that, at a certain compound interest rate, a sum of money deposited by anyone will become 8 times in 3 years. If the same amount is deposited at the same compound rate of interest, then in how many years will it become 16 times ?

The simple interest on a certain sum of money invested at a certain rate for 2 years amounts to Rs. 1200. The compound interest on the same sum of money invested at the same rate of interest for 2 years amounts to Rs. 1290. What was the principal?