The yield strength of a material is 200MPa when the grain size is 80 micron. If the frictional stress is 80MPa, find the strength when the grain diameter is 160 micron?

Correct Answer: 180 MPa
According to the hall-patch relationship: σo=σi+kD-1/2 -> 200=80+k(80)-1/2 -> k=1252 So at D=160 σo=80+1252(160)-1/2 σo=178.9 MPa.