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What is the mole fraction in instantaneous distillate if: Moles of liquid in residue at start W0= 1000 Moles of liquid in residue at end W= 600 Mole fraction in liquid at start X0 = 0.6 Mole fraction in liquid at end X= 0.5

Correct Answer: 0.75
XD = W0X0 –WX/W0-X, hence Xd= 0.75.

What is the mole fraction in instantaneous distillate if: Moles of liquid in residue at start W0= 1000 Moles of liquid in residue at end W= 500 Mole fraction in liquid at start X0 = 0.6 Mole fraction in liquid at end X= 0.5

What is the mole fraction in instantaneous distillate if: Moles of liquid in residue at start W0= 1000 Moles of liquid in residue at end W= 500 Mole fraction in liquid at start X0 = 0.5 Mole fraction in liquid at end X= 0.2

What is the mole fraction in instantaneous distillate if: Moles of liquid in residue at start W0= 1000 Moles of liquid in residue at end W= 500 Mole fraction in liquid at start X0 = 0.25 Mole fraction in liquid at end X= 0.1

What is the mole fraction in instantaneous distillate if: Moles of liquid in residue at start W0= 1000 Moles of liquid in residue at end W= 500 Mole fraction in liquid at start X0 = 0.7 Mole fraction in liquid at end X= 0.4

What is the mole fraction in instantaneous distillate if: Moles of liquid in residue at start W0= 1000 Moles of liquid in residue at end W= 300 Mole fraction in liquid at start X0 = 0.6 Mole fraction in liquid at end X= 0.5

What is the mole fraction in instantaneous distillate if: Moles of liquid in residue at start W0= 800 Moles of liquid in residue at end W= 500 Mole fraction in liquid at start X0 = 0.5 Mole fraction in liquid at end X= 0.1

What is the mole fraction in instantaneous distillate if: Moles of liquid in residue at start W0= 2000 Moles of liquid in residue at end W= 500 Mole fraction in liquid at start X0 = 0.3 Mole fraction in liquid at end X= 0.4

Find the distillate and the residue rates in mole/hr, if the feed rate is 100 mol/hr; The compositions of feed, distillate and residue in terms of mole fraction are 0.65, 0.9 and 0.2.

Compound A is extracted from a solution of A + B into a pure solvent S. A Co-current unit is used for the liquid-liquid extraction. The inlet rate of the solution containing A is 200 moles of B/hr.m2 and the solvent flow, rate is 400 moles of S/m2.hr. The equilibrium data is represented by Y = 3X2, where Y is in moles of a A/moles of B and X is in moles A/moles of S. The maximum percentage extraction achieved in the unit is

For a batch rectifier, R=1, Boilup rate = 100mol/hr Moles of liquid residue at start W0=100 Moles of liquid residue at end W= 50 Calculate time required for batch rectification.