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A gas mixture with 50% Ar with pressure 80 Pa at 0oC at the rate 5 liter/s is passed through a reactor and products a gas mixture with 80% Ar with pressure 50 Pa at 27oC, what is the rate of product?

Correct Answer: 5 liter/s
Ar balance: 0.5*80*5 = 0.8*50*P, => P = 5 liter/s.

A gas mixture with 20% O2 with pressure 100 Pa at 27oC at the rate 50 liter/s is passed through a reactor and products a gas mixture with 40% O2 with pressure 25 Pa at 27oC, what is the rate of product?

A gas mixture with 10% H2 with pressure 15 Pa at 27oC at the rate 20 liter/s is passed through a reactor and products a gas mixture with 30% H2 with pressure 25 Pa at 27oC, what is the rate of product?

A mixture with 60% O2 and 40% H2 with pressure 5 Pa at 27oC at the rate 15 liter/s is passed through a reactor with another stream containing pure H2 with pressure 10 Pa at 27oC at the rate 5 liter/s, what is the fraction of H2 with pressure 5 Pa at 27oC in product?

A gas mixture has 10% CH4 with pressure 5 Pa at 27oC at the rate F, is passed through a reactor with another stream containing 60% CH4 with pressure 5 Pa at -73oC at the rate 10 liter/s, if the percentage of CH4 with pressure 5 Pa at 27oC in product is 80%, what is the value of F?

A gas mixture with 6% O2 with pressure 1 atm at 27oC is entered a reactor with rate F, and another stream with pure O2 with 2 atm pressure at 27oC entered the reactor with rate 1 liter/s, product has 10% O2 with same conditions with rate P, what is the value of F?

A gas mixture with 5% Neon with pressure 10 atm at 27oC is entered a reactor with rate F, and another stream with pure Neon with 8 atm pressure at 27oC entered the reactor with rate 3 liter/s, product has 10% Neon with same conditions with rate P, what is the value of F?

A gas mixture with 20% Neon with pressure 3 atm at 27oC is entered a reactor with rate F, and another stream with pure Neon with 2 atm pressure at 27oC entered the reactor with rate 5 liter/s, product has 40% Neon with same conditions with rate P, what is the value of F?

From the 50 liters of milk, 5 liters of milk is taken out and after it 5 liters of water is added to the rest amount of milk. Again 5 liters of milk and water is drawn out and it was replaced by 5 liters of water. If this process is continued similarly for the third time, the amount of milk left after the third replacement:

The diluted wine contains only 8 liters of wine and the rest is water. A new mixture whose concentration is 30%, is to be formed by replacing wine. How many liters of mixture shall be replaced with pure wine if there was initially 32 liters of water in the mixture ?

A drink vendor has 80 liters of Mazza, 144 liters of Pepsi, and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required?