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A Closed U-tube manometer has a gas at one end and vacuum at other end, if the height difference of the liquid (density = 10 kg/m3) in the manometer in 5 cm, what is the pressure of the gas?

Correct Answer: 5 N/m2
Pressure of the gas = dgh = 10*10*0.05 = 5 N/m2.

A closed U-tube manometer has a gas on one end with pressure 10 Pa and other end has vacuum, what is the approximate density of the liquid if the height difference of the liquid is 10 cm?

A closed U-tube manometer has a gas on one end with pressure 5 Pa and other end has vacuum, what is the approximate height difference of the liquid if the density of liquid is 10 Kg/m3?

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The mixing vat in a factory receives liquid ingredients through six separate value--- labeled R.S.T.U,Y and Z -- each of which has exactly two settings: open and closed.The mixing vat operator must ensure that each valve is set open or closed according to the following conditions: If T is open, both S and Z must be closed, R and Z cannot both be closed at the same time; If Y is closed, Z must also be closed;S and U cannot both be open at the same time. If R is closed and U is open, which of the following must be true?

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A U-tube manometer is closed at both ends one end is vacuum and other end has a gas, if the difference in level of mercury is h = 10 mm, what is the pressure of gas?

Given that both liquid A and liquid B exert the same amount of pressure, what would be the height of column of liquid A if the density of liquid A is twice the density of liquid B and the height of column of liquid B is 10 cm?