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A Pickering governor is driving a gramophone. Each disc attached to the centre of a leaf spring has a mass of 20 g. The width of each spring is 5 mm and thickness of 0.125 mm. The effective length of each spring is 40 mm. The distance from the spindle axis to the centre of gravity of the mass when the governor is at rest, is 10 mm, find the speed of the turntable in rpm if ratio of the governor speed to the turntable speed is 10.5.

Correct Answer: 2.43
I = bt3/12 = 0.0008 (mm2)2 Length between fixed ends (L = 40-0.8 mm) Calculating delta from central deflection will give δ = 3.65 mm 3.65=0.51ω2 ω=2.675 rad/s N = 25.5 rpm N1 = 2.43 rpm.

A Pickering governor is driving a gramophone. Each disc attached to the centre of a leaf spring has a mass of 20 g. The width of each spring is 5 mm and thickness of 0.125 mm. The effective length of each spring is 40 mm. The distance from the spindle axis to the centre of gravity of the mass when the governor is at rest, is 10 mm. Find the speed of the governor in rpm when the sleeve has risen to a height of 0.8 mm. (E = 210kN/mm2)

From the data given: Dimensions of spring = 6mm wide, 0.12 mm thick and length = 48 mm mass attached to each leaf at centre = 25g Distance between spindle axis and C.O.M when the governor is at rest = 8mm Sleeve lift = 0.6mm E= 200 GN/mm2 Find the speed of the turntable in rpm if ratio of the governor speed to the turntable speed is 10.

From the following data calculate the speed of governor in rpm. Dimensions of spring = 6mm wide, 0.12 mm thick and length = 48 mm mass attached to each leaf at centre = 25g Distance between spindle axis and C.O.M when the governor is at rest = 8mm Sleeve lift = 0.6mm E = 200 GN/mm2

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