Find the deflection due to self weight given that ϕ = 1.6, Ee = 2.6Ece, elastic modulus of concrete is 34×103, gravity is given as 6, self weight is 0.76, Length of the cable is 1000, elastic modulus of concrete is 34×103 , Moment of inertia is 3200×105?

Correct Answer: 1.02mm
Ece = Ec/1+ϕ, ϕ = 1.6, Ee = 2.6Ece Deflection due to self weight g = (5gL4/384EcI) = (5×0.76×64x10004/384x34x103x3700x105) = 1.02mm.