A bar is in two sections having equal lengths. The area of cross section of 1st is double that of 2nd. if the bar carries an axial load of P, then what will be the ratio of elongation in section 2nd to section 1st ?

Correct Answer: 2
Ratio of elongation in 2nd / ratio of elongation in 1st = L2/L1 x A2/A1 Since L1 = L2 and A1 = 2A2 Therefore, ratio = 1 x 2/1 = 2.