The diameters of a pipe at the sections 1 and 2 are 8 cm and 13 cm respectively. Find the discharge through pipe if the velocity of water flowing through the pipe at section 1 is 6 m/s. Determine also the velocity at section 2.

Correct Answer: 2.27 m/s
According to continuity equation, Area × velocity = constant Area1*Velocity1 = Area2*Velocity2 Velocity2=(Area1*Velocity1)/Area2 = (82 * 6) / 132=2.27 m/s.